【单选题】
网考网参考答案:A
网考网解析:
Since the area of each small circle is πr 2 , the area of the white region is 3πr 2 . Also, since the area of the large circle is πR 2 , the shaded area is πR 2  -3πr 2  = π(R 2  -3r 2 ). Since the areas of the white region and the shaded region are equal:     3πr 2 =π(R 2 -3r 2 )[*] 3r 2 =R 2 -3r 2 [*]     [*]     which is greater than 2. Column A is greater.
                 
				 
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