【分析解答题】根据表1所列已知条件,写出螺距并计算出螺纹中径d2、内螺纹小径D、牙型高度,填入表中。
表 1
网考网解析:
试题答案:M12、(2)M48×2、(3)M16、(4)M36×3 (1)P=1.75mm d 2 =d-0.6495P=12mm-0.6495×1.75mm =10.863mm D 1 =d-1.0825P=12mm-1.0825×1.75mm =10.106mm h 1 =0.5413P=0.5413×1.75mm=0.9mm (2)p=2mm d 2 =d-0.6495P=48mm-0.6495×2mm =46.701mm D 1 =d-1.0825P=48mm-1.0825×2mm =45.835mm h 1 =0.5413P=0.5413×2mm=1.082mm (3)P=2mm d 2 =d-0.6495P=16mm-0.6495×2mm =14.701mm D 1 =d-1.0825P=16mm-1.0825×2mm =13.835mm h 1 =0.5413P=0.5413×2mm=1.082mm (4)P=3mm d 2 =d-0.6495P=36mm-0.6495×3mm =34.051mm D 1 =d-1.0825P=36mm-1.0825×3mm =32.753mm h 1 =0.5413P=0.5413×3mm=1.623mm 答案解析:暂无解析 document.getElementById("warp").style.display="none"; document.getElementById("content").style.display="block"; 查看试题解析出处>>
序号 | 螺纹代号 | 螺距P | 螺纹中径d2 | 内螺纹小径D1 | 牙型高度h1 |
1 | M12 | ||||
2 | M48×2 | ||||
3 | M16 | ||||
4 | M36×3 |
网考网解析:
试题答案:M12、(2)M48×2、(3)M16、(4)M36×3 (1)P=1.75mm d 2 =d-0.6495P=12mm-0.6495×1.75mm =10.863mm D 1 =d-1.0825P=12mm-1.0825×1.75mm =10.106mm h 1 =0.5413P=0.5413×1.75mm=0.9mm (2)p=2mm d 2 =d-0.6495P=48mm-0.6495×2mm =46.701mm D 1 =d-1.0825P=48mm-1.0825×2mm =45.835mm h 1 =0.5413P=0.5413×2mm=1.082mm (3)P=2mm d 2 =d-0.6495P=16mm-0.6495×2mm =14.701mm D 1 =d-1.0825P=16mm-1.0825×2mm =13.835mm h 1 =0.5413P=0.5413×2mm=1.082mm (4)P=3mm d 2 =d-0.6495P=36mm-0.6495×3mm =34.051mm D 1 =d-1.0825P=36mm-1.0825×3mm =32.753mm h 1 =0.5413P=0.5413×3mm=1.623mm 答案解析:暂无解析 document.getElementById("warp").style.display="none"; document.getElementById("content").style.display="block"; 查看试题解析出处>>
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