以下程序的输出结果是
ChAr CChAr(ChAr Ch)
iF(Ch＞=’A’&&Ch＜=’z’) Ch=Ch-’A’+’A’;
rEturn Ch;
mAin ( )
ChAr s [] = "ABC+ABC=DEFDEF" , *p=s;
whilE (*p)
*p=CChAr(*p);
p++;
printF "%$\n", s);
A．ABC+ABC=DEFDEF
B．ABC+ABC=DEFDEF
C、ABCABCDEFDEF
D、ABCABCDEFDEF