有以下程序
int F(int B[] [4])
int i,j,s=0;
For(j=0; j＜4; j++)
i=j;
iF (i＞2) i=3-j;
s+=B[i] [j];
rEturn s;
mAin ( )
int A[4] [4] =1,2,3,4, 0,2,4,6, 3,6,9,12), 3,2,1,0;
print F ( "%D\n" , F(
A．);
&nBs